解答
219
SQL文(クエリ)
WITH master AS (
SELECT
user_id
, SUM(revenue) AS sum_rev
FROM
sample.sales
GROUP BY
user_id
)
SELECT
ROUND(COUNT(*) / (
SELECT
COUNT(DISTINCT user_id)
FROM
master
), 3) AS user_accum_percentage
, ROUND(MAX(accum_sum_rev) / (
SELECT
SUM(sum_rev)
FROM
master
), 3) AS rev_accum_percentage
FROM
(
SELECT
user_id
, SUM(sum_rev) OVER (ORDER BY sum_rev DESC)
AS accum_sum_rev
FROM
master
ORDER BY
sum_rev DESC
LIMIT 100
)



